1. You will need your ticker code (show your ticker code on your homework and in

Question

1. You will need your ticker code (show your ticker code on your homework and include a printout of the data!) for stock prices for this question. Use your ticker code to obtain the closing prices for the following three time periods to obtain three data sets:

March 2, 2016 to March 16, 2016

Data set A: .03, .02, .02, .02, .02, .02, .02, .00

March 17, 2016 to March 31, 2016

Data set B: .03, .03, .01, .03, .01, .01, .01, .02

April 1, 2016 to April 17, 2016

Data set C: .02, .02, .02, .02, .02, .05

Imagine you are testing for the effects of two experimental drugs (data sets B and C) relative to a control group (Data set A) on a physiological variable.

a)Conduct an ANOVA on the data set. Show all calculations, table of results, and state your conclusion.

b)Use the Bonferroni-Holm (regardless of whether part “a” is significant or not) to examine all pairwise comparisons. Show all you calculations and state your conclusions.

Explanation / Answer

following information has been generated using ms-excel

we use one-way anova with

null hypothesis H0:mean(A)=mean(B)=mean(C)

alternate hypothesis H1: atleast one differ from another

here p-value of F of between set is more than alpha=0.05, so we fail to reject H0.

(b) here we have there are 3-pair of comparison=n=3C2

least significant difference =lsd=sqrt(mse*(1/r1+1/r2)*t(alpha/3,error df)

bonferroni procedure of calculation of least significant difference

lsd for A and B=sqrt(0.0001*(1/8+1/8))*t(0.05/3,19)=sqrt(0.0001*(1/8+1/8))*2.63=0.0132

lsd for A and C=sqrt(0.0001*(1/8+1/6))*t(0.05/3,19)=sqrt(0.0001*(1/8+1/6))*2.63=0.0142

( difference=0.025-0.01875=0.00625)

lsd for B and C=sqrt(0.0001*(1/8+1/8))*t(0.05/3,19)=sqrt(0.0001*(1/8+1/8))*2.63=0.0132

( difference=0.025-0.01875=0.00625)

since non of the difference is more than the corresponding lsd, so no pair is significantly different to one another

SetA SetB SetC Anova: Single Factor 0.03 0.03 0.02 0.02 0.03 0.02 SUMMARY 0.02 0.01 0.02 Groups Count Sum Average Variance 0.02 0.03 0.02 Column 1 8 0.15 0.01875 6.96E-05 0.02 0.01 0.02 Column 2 8 0.15 0.01875 9.82E-05 0.02 0.01 0.05 Column 3 6 0.15 0.025 0.00015 0.02 0.01 0 0.02 ANOVA Source of Variation SS df MS F P-value F crit Between Groups 0.00017 2 8.52E-05 0.841204 0.446631 3.521893 Within Groups 0.001925 19 0.000101 Total 0.002095 21

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