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STAT-3001-5/STAT-3001L-SISTAT-3001P-6-Statistical Methods2017 Winter Qtr 11/27-0

ID: 3350335 • Letter: S

Question

STAT-3001-5/STAT-3001L-SISTAT-3001P-6-Statistical Methods2017 Winter Qtr 11/27-0 Test: Week 6 Exam This Question: 2 pts 2/18-PT3 Time Remaining: 04 40 49 Submit Test 28 of This Test: 100 pts possib The values in the table below are measured occurred with dick the icon to view the table. Find the P-value (in millimeters) of male skulls from different epochs Changes in head shape over time suggest thet mmigrant populations. Use a 0 05 significance level to test the claim that the different epochs all have the same mean O A. There is sufficient evidence to reject the claim that the different epochs have the same mean O B. There is not sufficient evidence to reject the claim that the different epochs have the same mean 4000 B.C 1850 B.C 150 AD. 128 138 136 130 138 125 129 133 135 132 134 137 129 134 136 137 137 127 136 138 134 141 142 137 145 Click to select your answer(s)

Explanation / Answer

The problem is analysed by one-way ANOVA with equal number of observations per block.

p-value = 0.03 ANSWER 1

Conclusion: option A ANSWER 2

Elaborate details are presented below for better understanding and comprehension of the working of the solution.

Back-up Theory

Suppose we have data of a 1-way classification ANOVA, with r rows/treatments and n observations per cell/treatment.

Let xij represent the jth observation in the ith row, j = 1,2,…,n; i = 1,2,……,r

Then the ANOVA model is: xij = µ + i + ij, where µ = common effect, i = effect of ith row, and ij is the error component which is assumed to be Normally Distributed with mean 0 and variance 2.

Null hypothesis: H0: 1 = 2 = 3 = 0 Vs Alternative: HA: H0 is false

Now, to work out the solution,

Terminology:

Row total = xi.= sum over j of xij

Grand total = G = sum over i of xi.

Correction Factor = C = G2/N, where N = total number of observations = r x n =

Total Sum of Squares: SST = (sum over i,j of xij2) – C

Row Sum of Squares: SSR = {(sum over i of xi.2)/(n)} – C

Error Sum of Squares: SSE = SST – SSR

Mean Sum of Squares = Sum of squares/Degrees of Freedom

Fcrit: upper % point of F-Distribution with degrees of freedom n1 and n2, where n1 is the DF for Row and n2 is the DF for Error

Significance: Fobs is significant if Fobs > Fcrit

       ANOVA TABLE      

Source of

Variation

Degrees of Freedom (DF)

Sum of squares (SS)

Mean Sum

of squares

(MS = SS/DF)

Fobs

Fcrit*

Significance**

Row

r - 1

SSR

MSR/MSE

Error

rn - r

SSE

Total

rn - 1

SST

     NOTE:

     * Fcrit: upper % point of F-Distribution with degrees of freedom n1 and n2, where n1

     is the DF for Row and n2 is the DF for Error

     ** Significance: Fobs is significant if Fobs > Fcrit

Calculations

Let xij = maximum breadth of male skull belonging to epoch i, i = 1 for BC 2000, 2 for BC 1850 and 3 for AD 150 and j = 1, 2, ….. , 9.

Excel calculation summary:

alpha

0.05

#treat

3

n1

9

n2

9

n3

9

n

27

x1.

1193

x2.

1208

x3.

1243

G = x..

3644

C

491805

Sx1j^2

158273

Sx2j^2

162256

Sx3j^2

171853

Sxij^2

492382

Sxi.^2/ni

491951.3

SST

576.963

SSR

146.2963

SSE

430.6667

ANOVA TABLE

Source

DF

SS

MS

F

Fcrit

p-value

Epoch

2

146.3

73.14815

4.076367

3.4028261

0.0299171

Error

24

430.67

17.94444

Total

26

576.96

22.19088

Since p-value < 0.05 (given level of significance), H0 is rejected. => there is not enough evidence to suggest that the mean skull breadths remained the same over the epochs.

DONE

Source of

Variation

Degrees of Freedom (DF)

Sum of squares (SS)

Mean Sum

of squares

(MS = SS/DF)

Fobs

Fcrit*

Significance**

Row

r - 1

SSR

MSR/MSE

Error

rn - r

SSE

Total

rn - 1

SST