A company make lunch coupons for 122 students but it\'s products 118 lunch meals

Question

A company make lunch coupons for 122 students but it's products 118 lunch meals to avoid loss , probability that students come to the lunch 0.9
1- probability that all students come to lunch will find meals.
2- probability no lunch remaining. A company make lunch coupons for 122 students but it's products 118 lunch meals to avoid loss , probability that students come to the lunch 0.9
1- probability that all students come to lunch will find meals.
2- probability no lunch remaining. A company make lunch coupons for 122 students but it's products 118 lunch meals to avoid loss , probability that students come to the lunch 0.9
1- probability that all students come to lunch will find meals.
2- probability no lunch remaining.

Explanation / Answer

Solution:-

n = 122

p = 0.90

1) The probability that all students come to lunch will find meals is 0.9987.

x = 118

By applying binomial distribution:-

P(x, n) = nCx px (1-p)(n-x)

P(x < 118) = 0.9987

2) The probability no lunch remaining is 0.00484.

x = 118

By applying binomial distribution:-

P(x, n) = nCx px (1-p)(n-x)

P(x > 118) = 0.00484

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