Ls4202_biostatistics_midsem_2018_ please answer only question no.5. Biostatistic

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Ls4202_biostatistics_midsem_2018_
please answer only question no.5.

Biostatisticsl 54202 SampleQuestions Microsoht Wond e Leyout Reterences Malings Review View is auieast4 Q5. A Harpy Eagle (Harpiaharpyja) pair raises one chick every 2 years. If the pair successfully raises a chick in a cycle, its chance of successfully raising a chick in the next two-year cycle is 0.8. On the other hand, if the pair fails to raise a chick in a cycle, the eagles chance of raising a chick in the next cycle is 0.6.What is the probability that the Harpy parents have raised three chicks at the end of three successive cycles? 06.Suppose now that events A. B and C are mutually independent with P(A) 0.3, P(B)-0.4. and P(C)-0.5. Compute/show the following: (Hint: Use a Venn diagram. All values below can be obtained by simply partitioning components in the Venn diagram) (A) Compute all possible intersectious of 2 and 3 events and indicate in the Venn diagram (B) Indicate the following in the Venn diagram: (PABnC(i) P(AnBnC) and (iii) PAn BnC) and compute the values. Q7·suppose that X takes values between l and 5 and has probability density function

Explanation / Answer

Let the three successive cycles in which the eagles have successfully raised a chick each be named 1,2,3.

The probability of raising a Chick successfully in cycle 1 is dependent on the event whether the parents raised a chick successfully in cycle 0.

If they raised a chick successfully in cycle 0, then the probability of raising a Chick successfully in each of the cycles 1,2 and 3 is given as 0.8 x 0.8 x 0.8.

If the parents failed to successfully raise a chick in cycle 0, then the probability of raising a Chick successfully in each of the cycles 1,2 and 3 is given as 0.6 x 0.8 x 0.8.

So the total probability of raising a Chick successfully in each of the cycles 1,2 & 3 = 0.8 x 0.8 x 0.8 + 0.6 x 0.8 x 0.8 = 0.896

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