Give the 95% Confidence inte Give a co nclusf ion for the confidence interval te

Question

Give the 95% Confidence inte Give a co nclusf ion for the confidence interval test is Test of 2 Proportions ional courtesy, physiclans have traditionally provided health care free of charge or rate to other physicians and their families. In 1986, 94% of a sample of 1,000 4. AS a profess at reduced ns offered thls professional courtesy. To assess the extent to which this practice has physicia hneed over the years, The New England Journal of Medicine conducted a survey of 2,224 physicians of which Test statisticz n1+12 State the null and alternative hypothesis. State your conciusion for your hypothesis test. 4 points 4 points Chi-Square Goodness of Fit Test.

Explanation / Answer

Given that,
sample one, x1 =940, n1 =1000, p1= x1/n1=0.94
sample two, x2 =1957, n2 =2224, p2= x2/n2=0.8799
null, Ho: p1 = p2
alternate, H1: p1 != p2
level of significance, = 0.05
from standard normal table, two tailed z /2 =1.96
since our test is two-tailed
reject Ho, if zo < -1.96 OR if zo > 1.96
we use test statistic (z) = (p1-p2)/(p^q^(1/n1+1/n2))
zo =(0.94-0.8799)/sqrt((0.899*0.1014(1/1000+1/2224))
zo =5.2247
| zo | =5.2247
critical value
the value of |z | at los 0.05% is 1.96
we got |zo| =5.225 & | z | =1.96
make decision
hence value of | zo | > | z | and here we reject Ho
p-value: two tailed ( double the one tail ) - Ha : ( p != 5.2247 ) = 0
hence value of p0.05 > 0,here we reject Ho
ANSWERS
---------------
null, Ho: p1 = p2
alternate, H1: p1 != p2
test statistic: 5.2247
critical value: -1.96 , 1.96
decision: reject Ho
p-value: 0

signifincance diffrence between the when coompared to both proportion rate

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