Bag Plate gap (X) Tear rating (Y) 1 0 0.01 2 0.30 0.07 3 1.50 0.43 4 2.10 0.84 5
ID: 3325471 • Letter: B
Question
Bag
Plate gap
(X)
Tear rating
(Y)
1
0
0.01
2
0.30
0.07
3
1.50
0.43
4
2.10
0.84
5
0.30
0.37
6
0.30
0.32
7
0.30
0.72
8
0.30
1.94
9
0.30
0.26
10
1.80
0.16
11
1.50
0.11
12
2.40
3.99
13
1.50
0.01
14
0.00
0.54
15
3.00
0.09
16
2.10
0.13
17
1.80
0.42
18
1.80
4.14
19
0.30
0.05
Bag
Plate gap
(X)
Tear rating
(Y)
1
0
0.01
2
0.30
0.07
3
1.50
0.43
4
2.10
0.84
5
0.30
0.37
6
0.30
0.32
7
0.30
0.72
8
0.30
1.94
9
0.30
0.26
10
1.80
0.16
11
1.50
0.11
12
2.40
3.99
13
1.50
0.01
14
0.00
0.54
15
3.00
0.09
16
2.10
0.13
17
1.80
0.42
18
1.80
4.14
19
0.30
0.05
2.8.59-T experiment was conducted to determine the factors in the bag-sealing equipment that might be affecting the ease of opening the bags without tearing the innet liner of the bag. Data were collected on 19 bags and the plate gap on the bag-sealing equipment was used to predict the tear rating of a bag. Complete parts (a) through (c). EE click the icon to view the data table. a. Construct a 95% confidence interval estimate of the mean tear rating for all bags of coffee when the plate gap is 03 (Type integers or decimals. Round to three decimal places as needed. Use ascending order.) Enter your answer in the edit fielis andd then click ChoExplanation / Answer
The formula for estimation is:
= M ± Z(sM)
where:
M = sample mean
Z = Z statistic determined by confidence level
sM = standard error = (s2/n)
Calculation
M = 0.90333
t = 1.96
sM = (0.9582452/3) = 0.55
= M ± Z(sM)
= 0.90333 ± 1.96*0.55
= 0.90333 ± 1.0843364
M = 0.90333, 95% CI [-0.1810064, 1.9876664].
You can be 95% confident that the population mean () falls between -0.181 and 1.988.
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