For questions 9 through 11, base your answers on the discrete probability distri

Question

For questions 9 through 11, base your answers on the discrete probability distribution which represents the number of males with a certain genetic trait for a sample of five randomly selected males 0 0.07 1 0.25 2 0.38 3 0.20 4 0.08 5 0.02 9. What is the probability that two of the five males have that genetic trait? a) 0.32 b) 0.38 c) 0.40 d) 0.68 10 What is the probability that more than three of the five males have that genetic trait? 10. a) 0.10 b) 0.20 c) 0.30 d) 0.90 What is the mean number (or expected value) of males that have that genetic trait? 11. a) 2.03 b) 2.10 c) 2.50 d) 3.0S The question below is separate from questions 9 through II above. The U.S. Census Bureau states that in America, 40% of first marriages end in divorce. In a random sample of five (5) first marriages, what is the probability that at most one of those first marriages end in divorce? 12· 12. a) 0.259 b) 0.337 c) 0.663 d) 0.741

Explanation / Answer

9) P(X = 2) = 0.38

Option-B) 0.38

10) P(X > 3) = P(X = 4) + P(X = 5) = 0.08 + 0.02 = 0.1

Option-A) 0.1

11) mean = E(X) = 0 * 0.7 + 1 * 0.25 + 2 * 0.38 + 3 * 0.2 + 4 * 0.08 + 5 * 0.02 = 2.03

Option-A) 2.03

12) p = 0.40

n = 5

P(X < 1) = P(X = 0) + P(X = 1)

= 5C0 * 0.40 * 0.65 + 5C1 * 0.41 * 0.64

= 0.337

Option-B) 0.337

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