I assumed that velocity was the response and X was the factor tp create the scat

Question

I assumed that velocity was the response and X was the factor tp create the scatter plot but I'm not sure if that's even right....

| N -Bivariate Fit of Velocity By Depth c secure http://www.webassign net web Student Assignment Responses su mit?deo:1759 466 ::: Apps Q Quizlet e Chegg G Google Facebook( has lells Fargo USAA ·PayPal BTJ BTU A Atmos Energy R Home | Howdy : 1.4 12 10. 04 points Previous AneNCS My Notes Ask Your The velocity of a river is controlled by a variety of factors and the highest velocity is usually in the deepest part of the channel, just below the surface. This data was acquired below the Grand Coulee Dam at a distance 13 feet trom the edge of the river. The depth at that location is measured in teet and the velocity in tt per second. 09 0% 0.4 depth 30 3545 60 70 75 8.7 9.9 10.6 velocity 1.551.11 1.39 1.39 1.14 0.91 0.59 0.59 0.41 0 10 230 40 50 070 80 9 Depth (a) Find the equation of the least-squares (linear regression) line for the data. (Round coefficients to 4 decimal places.) _ Linear fil y-7258 Usc the (h) At what depth does model say the river has a speed of 0.7 ft/sec? Round your answer to twn decimal places × x + 0076 , Linear Fit e regression equation to answer these questions. Velccity 0.7258293 0.0076546 Depth Summary of Fit RSquare RSquare Adj Root Mean Square Errer 0388166 Mean of Response Ctservations (or Sun Wgls) 0238002 1014444 () Predit the velocity of the river at the depth of 20ft. Round your answer to three decial places. Analysis of Variance Sum of Source DF Squares Mean Square FRatio Model Error C. Total 1 0.3300824 0.330002 219T3 7 1.056338 0.15090 ProbF 8 1.3864222 0.1827

Explanation / Answer

We have excel output for regression as :

a) The regression equation is

Velocity = 0.6730 + 0.0088 * Depth

b) Here we have velocity = 0.7

Velocity = 0.6730 + 0.0088 * Depth

0.7 = 0.6730 + 0.0088 * Depth

0.7 - 0.6730 = 0.0088 * Depth

Depth = 3.07

c) Here we have Depth = 20

Velocity = 0.6730 + 0.0088 * Depth

Velocity = 0.6730 + 0.0088 * 20

= 0.849

SUMMARY OUTPUT Regression Statistics Multiple R 0.559977 R Square 0.313574 Adjusted R Square 0.215513 Standard Error 0.36115 Observations 9 ANOVA df SS MS F Significance F Regression 1 0.417081 0.417081 3.19775 0.116881 Residual 7 0.913007 0.13043 Total 8 1.330089 Coefficients Standard Error t Stat P-value Lower 95% Upper 95% Intercept 0.672965 0.223117 3.016205 0.019491 0.145378 1.200552 Depth 0.008786 0.004913 1.788225 0.116881 -0.00283 0.020404

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