I ask because my professor calculated t1 (3.9) with F1 (150). I don’t understand

Question

I ask because my professor calculated t1 (3.9) with F1 (150).
I don’t understand why he would use N for t2? LN (PI) P1 PI pegl pegl L2(PI igure 3a Moment arms are measured about "O" Figure 3b Moment arms are measured about " n the sheet for measurement #1, the force lines of F1 and F, , the contact point "O" (where the ce d makes contact with the plate) should be marked. Extend the force lines of F, and F, to measure between them (Fig. 3a). Calculate the resultant force F = F + (both magnitude |F and the direction 6, ). Find the normal force N (both magnitude and the direction .) Draw the moment arms L (O) and L: (0) of forces about point "O" (Fig. 3a). Determine the torques of F.. F, and N about point"O". Record all the values in Table 1. Draw the moment arms L: (Pl) and L(P) of the forces about point "Pl" which is the acting F, (Fig. 3b). Determine the torques of F, and N about point "PI" Record all the values with units in Table 1 Results of Measurement #1 error about point about point 1,50 | "PI" easurement #2: Two forces!F-ng, F-m2g(g=9.80 m/s) from the pegl and ch that the strings make an angle between 100° 120°, where m, 0.150 kg, m2-0.3 the sheet for measurement #2, the force lines of F, and F, , the contact point "O" (where the makes contact with the plate) are marked.

Explanation / Answer

Here in the above questionit is wrong to multiply

N with L2.because (torque)2.is the multiplication

of F2 with l2.we know torque is the

vector multiplication perpendicular force to

distance to the observation point....Hope this answer

is helpful

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