iPad 8:18 PM * 87%- webassign.net You may need to use the appropriate table in t
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iPad 8:18 PM * 87%- webassign.net You may need to use the appropriate table in the Appendix of Tables to answer this question. Need Help? Read It Viewing Saved Work Revert to Last Response 5.+-/10 points DevoreStat7 5.P050 My Notes Ask Your Te The breaking strength of a rivet has a mean value of 10,100 psi and a standard deviation of 498 psi. (a) What is the probability that the sample mean breaking strength for a random sample of 40 rivets is between 10,00 and 10,300? (Give answer accurate to 3 decimal places.) 1.0836 (b) If the sample size had been 15 rather than 40, could the probability requested in part (a) be calculated from the gi information? Explain your reasoning. Yes, the probability in part (a) can still be calculated from the given information No, according to the Rule of Thumb n should be greater than 30 in order to apply the C.L.T No, according to the Rule of Thumb n should be greater than 25 in order to apply the C.L.T O No, according to the Law of Large Numbers n should be greater than 30 in order to apply the C.L.T You may need to use the appropriate table in the Appendix of Tables to answer this question. Need Help? Read It Viewing Saved Work Revert to Last Response 6. -/10 points DevoreStat7 5.P.038 My Notes Ask Your Te There are two traffic lights on my way to work, Let X1 be the number of lights at which I must stop, and suppose that theExplanation / Answer
(a) Given: µ = 10,100 psi, = 498 psi, n = 40
To find the probability, we need to find the Z scores first.
Z = (X - µ)/ [/n].
n = 40, To calculate P (10,000 < X < 10,300) = P(X < 10,300) – P(X < 10,000)
For P( X < 10,300)
Z = (10,300 – 10,100)/[498/40] = 2.54
The probability for P(X < 10,300) from the normal distribution tables is = 0.994
For P( X < 10,000)
Z = (10,000 – 10,100)/[498/40] = -1.27
The probability for P(X < 10,000) from the normal distribution tables is = 0.102
Therefore the required probability is 0.994 – 0.102 = 0.892
(b) Yes, the probability in part (a) can still be calculated from the given information.
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