iPad 6% 2:24 PM Chapter 15 x My options x Chegg.com C D www.webassign.net/web/St
ID: 1406622 • Letter: I
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iPad 6% 2:24 PM Chapter 15 x My options x Chegg.com C D www.webassign.net/web/Student/Assignment Responses/last?dep 12337362 14 -11 points SerCP10 15. P.029. My Notes Ask Your Teacher Three identical charges (q 3.8 ALC) lie along a circle of radius 1.8 m at angles of 300, 150 and 2700, as shown in the figure below. What is the resultant electric field at the center of the circle? N/C 80 270° Need Help? Read It 15 12 points SerCP10 15. P.030 My Notes Ask Your Teacher The figure below shows the electric field lines for two point charges separated by a small distance.Explanation / Answer
Because the picture is symmetric and all charges are equal, resultant electric field at the center will be zero.
I see they're 3 equally spaced charges, at 120 degree intervals, so it's making sense that the field from each would cancel out in the end.
First, what do you get for the field due to just one charge?
k*q/r^2 = 10543.8 N/C, directed toward the charge.
For x-components of the field, using
Ex = 10543.8*cos(angle)
I'm getting
9131.2, -9131, and 0 N/C for each of the charges. These add up to 0.
For the y-components, use
Ey = 10543.8*sin(angle).
I'm getting
5271.9, -5271.9, and -10543.8 N/C for each of the charges. These also add up to 0.
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