iPad 5:43 PM 100% chegg.com Chegg Study TEXTBOOK SOLUTIONS EXPERT ORA Search me

Question

iPad 5:43 PM 100% chegg.com Chegg Study TEXTBOOK SOLUTIONS EXPERT ORA Search me / study engineering/mechanical engineering/machine design/ machine design solutions manuals/ machine design/3rd edition / chapte achine Design |(3rd Edition) Chapter 3, Problem 3P Show all steps: Bookmark Problem A 45 kg crate rests on two rollers 100 mm in diameter. If the coefficient of rolling resistance is 2.5 mm (both top and bottom), how much horizontal force must be applied to the crate to put it in motion? Step-by-step solution ro There is no solution to this problem yet. Get help from a Chegg subject expert ASK AN EXPERT

Explanation / Answer

Horizontal force applied on crate to put it on motion F=(C/r)*(mg)

Here, m is. Mass of cylinder

r is radius of cylinder

C is rolling resistance

Hence, F = (2.5/50)*(45*9.81)

= 22.0725 N. .......ans

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.