27. Assume that the given procedure yields a binomial distribution with n trials

Question

27. Assume that the given procedure yields a binomial distribution with n trials and the probability of success for one trial is p Use the given values of n and p to find the mean and standard deviation o. Also, use the range rule of thumb to find the minimum usual value -2 and the maximum usual value +2 In an analysis of preliminary test results from a gender-selection method, 48 babies are born and it is assumed that 50% of babies are girls, so n-48 and p=0.5 The value of the mean is . (Simplify your answer) (Round to one decimal place as needed.) (Round to one decimal place as needed.) (Round to one decimal place as needed.) The value of the standard deviation is The minimum usual value is -2 = The maximum usual value is +2 9/30/2017 https://xlitemprod.pearsoncmg.com/api/v1/print/math

Explanation / Answer

Denoting the girls by 1 and boys by 0, we have 24 0s and 24 1s (since probability is 0.5)

=> Mean = (24*0+24*1)/48

= 24/48 = 0.5

Sum of squares of differences = 24*(0 - 0.5)2 + 24*(1 - 0.5)2

= 48*0.52

= 48*0.25

= 12

Variance = 12/48 = 0.25

Standard deviation = 0.25 = 0.5

The minimum usual value is 0.25 - 2*0.5 = -0.75

The maximum usual value is 0.25 + 2*0.5 = 1.25

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