A pizza shop claims its average home delivery time is 33 minutes. A sample of 50

Question

A pizza shop claims its average home delivery time is 33 minutes. A sample of 50 deliveries had a sample average of 34.9 minutes. Assume the population standard deviation for the shop's deliveries is 6.6 minutes. Complete parts a and b below. a. s there support for the shop's claim using the criteria that the sample average of 34.9 minutes falls within the symmetrical interval that includes 95% of the sample means if the true population mean is 33 minutes? Select the correct choice below and fill in the answer box within your choice. (Type an integer or decimal rounded to four decimal places as needed.) A. The probability P(x greaterthanorequalto 34.9) = This indicates that the sample average of 34.9 minutes falls outside the 95% symmetrical interval, contradicting the shop's claim. B The probability P(x greaterthanorequalto 34.9) = This indicates that the sample average of 34.9 minutes falls within the 95% symmetrical interval, s he shop's claim.

Explanation / Answer

here std error of mean =std deviation/(n)1/2 =0.9334

therefore P(X>34.9)=P(Z>(34.9-33)/0.9334)=P(Z>2.0356)=0.0209

therefore option A is correct.

with P(X>34.9)=0.0209

please revert for any clarification required

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