16.1111 28 23e- 16.1111 27-22 e o w) 16, 1111= 27-22ek(10 + w) 61-27-22e-w 16.11

Question

16.1111 28 23e- 16.1111 27-22 e o w) 16, 1111= 27-22ek(10 + w) 61-27-22e-w 16.111127- 22e-kw 16. 111127- 22 e k w none of the above, specify: Problem #5 (25 points totally) At 8:10:03 am, a projectile was launched from the ground. altitude achieved by the projectile were obtained: By means of a radar, the following data about the Altitude (in meters) 8:10:03 am 8:10:05 am 8:10:08 am 277 552 Question: What was the highest altitude that was achieved by the projectile? Round-off your result for the maximum of the altitude (measured in meters) to three figures and present below (13 points): (your numerical result must be written here) Hints The projectile was launched strictly upwards.

Explanation / Answer

t = 0 , h = 0

t = 2s , h = 277

t = 5s, h = 522

h = ut+0.5at2

277 = 2u + 0.5 a * 4

=> 277 = 2u + 2a

=> u + a = 277/2 = 138.5

=> u = (138.5 - a)

and

522 = 5u + 0.5 *a * 25

=> 522 = 5u + 12.5 a

=> 522 = 5 ( 138.5 - a ) + 12.5a

=> 522 = 692.5 - 5a + 12.5a

=> -170 = 7.5a

=> a = -170/7.5 = -22.733

u = 138.5 - (-22.733) = 161.233

Now ,

v2 - u2 = 2ah

At h max , v = 0

therefore

h max = -u2 / 2a = -(161.233)2 / (2 * -22.733 ) = 571.769 m

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