Part A Problem 31.58 Find the current amplitude in the resistor A 400- resistor

Question

Part A Problem 31.58 Find the current amplitude in the resistor A 400- resistor and a 5.60-F capacitor are connected in parallel to an ac generator that supplies an rms voltage of 220 V at an angular frequency of 360 rad/s Note that since there is no inductor in the circuit, the 1/ term is not present in the expression for Z Submit My Answers Give Up Part B Find the current amplitude in the capacitor Part D Submit My Answers Give Up Find the amplitude of the current through the generator Part C Find the phase angle of the source current with respect to the source voltage Submit My Answers Give Up

Explanation / Answer

a) current amplitude = Vrms * sqrt 2 / R

= 220 * sqrt 2 / 400

= 0.778 A

b) Imax = Vrms * sqrt 2 * w c

= 220 * sqrt 2 * 360 * 5.6 * 10-6

= 0.627 A

c) theta = tan-1 [w R C]

= tan-1 [360 * 400 * 5.6 * 10-6]

= 38.88 deg

d) amplitude of current = Vmax / Z = Vmax * sqrt [1/R2 + (wC)2]

= 220 * sqrt 2 * sqrt [1/4002 + (360 * 5.6 * 10-6)2]

= 0.999 A

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