Part A Part B If the same experiment were performed on a lead cube of the same s
ID: 2145057 • Letter: P
Question
Part A Part B If the same experiment were performed on a lead cube of the same size as the copper one, by what distance would it deform for the same force as in part B? PLEASE HELP ME WITH THIS! <3 Part B If the same experiment were performed on a lead cube of the same size as the copper one, by what distance would it deform for the same force as in part B? PLEASE HELP ME WITH THIS! <3 Part B If the same experiment were performed on a lead cube of the same size as the copper one, by what distance would it deform for the same force as in part B? PLEASE HELP ME WITH THIS! <3 Part B If the same experiment were performed on a lead cube of the same size as the copper one, by what distance would it deform for the same force as in part B? PLEASE HELP ME WITH THIS! <3 Part B If the same experiment were performed on a lead cube of the same size as the copper one, by what distance would it deform for the same force as in part B? PLEASE HELP ME WITH THIS! <3 ELASTICITY / DEFORM - BASIC HIGHSCHOOL/COLLEGE PHYSICS A copper cube measures 6.24cm on each side. The bottom face is held in place by very strong glue to a flat horizontal surface, while a horizontal force is applied to the upper face parallel to one of the edges. How large must be to cause the cube to deform by 0.295mm? If the same experiment were performed on a lead cube of the same size as the copper one, by what distance would it deform for the same force as in PLEASE HELP ME WITH THIS!Explanation / Answer
shear modulus of copper = 45 GPa
shear modulus of lead = 13.1 Gpa
G = FL / A?x
For copper, 45* 10^9 = F* 0.0624 / (0.0624)^2*(0.000295)
So, F = 828360 N
For lead:
?x = FL/AG = 828360*0.0624 / ((0.0624^2)*13.1x10^9)=1.00*10^-3 m
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