Part A Part B In what direction does the current flow in the rod? PartD:Find the

Question

Part A

Part B

In what direction does the current flow in the rod?

PartD:Find the magnitude of the force mentioned in part (C).

a.Use a step_up transformer with N2/N1 = 2.

or b.Use a step_down transformer with N2/N1 = 1/2

PartB:What current will your blower draw from a European outlet?What resistance will your blower appear to have when operated at 240V ?

Part C:What resistance will your blower appear to have when operated at 240V ?

You plan to take your hair blower to Europe, where the electrical outlets put out 240V instead of the 120Vseen in the United States. The blower puts out 1640W at 120V.PArt A:What could you do to operate your blower via the 240V +y direction? T that points in the +y B = 0.212T +z direction?PartC:What is the magnitude of the magnetic flux through this circle due to a uniform magnetic field B degree from the +z T that points at an angle of 52.6? B = 0.212T +z direction?PartB:What is the magnitude of the magnetic flux through this circle due to a uniform magnetic field B T that points in the +z B = 0.212T y plane.PartA:What is the magnitude of the magnetic flux through this circle due to a uniform magnetic field B x-y cm lies in the x s .PArtA:What is the average induced emf in the secondary coil? Question3: A circular area with a radius of 6.80cm A} . A secondary winding of 2.00 turns encircles the solenoid at its center. When the primary circuit is opened, the magnetic field of the solenoid becomes zero in 5.00½10?2s cm^{2} is wound with 40.0 turns of wire per centimeter, and the windings carry a current of 0.250A m/s . PartD:Find the magnitude of the force mentioned in part (C). Question2:A very long, straight solenoid with a cross-sectional area of 6.00cm2 Omega , find the direction of the force required to keep the rod moving to the right with a constant speed of 9.00m/s abcd is a constant 3.00?, m/s . Part B In what direction does the current flow in the rod? PArtC:If the resistance of the circuit abcd no title provided Part A Find the magnitude of the emf induced in the rod when it is moving toward the right with a speed 9.00m/s T} , perpendicular to the plane of the figure.:db. The apparatus is in a uniform magnetic field of 0.850T ca and db ab shown in the figure (Figure 1) makes frictionless contact with metal rails ca V} ? Question2The conducting rod ab V} ? Part C:What resistance will your blower appear to have when operated at 240V {N_2}/{N_1} = 1/2 PartB:What current will your blower draw from a European outlet?What resistance will your blower appear to have when operated at 240V {N_2}/{N_1} = 2. or b.Use a step_down transformer with N2/N1 V} line in Europe? a.Use a step_up transformer with N2/N1

Explanation / Answer

Question 1:

Transformer turns Ratio

N2/N1 =V2/V1 =I1/I2

a)

Step Down Transformer to be used with turns ratio

N2/N1 =120/240 =1/2

b)

Current drawn by blower is

I2=P/V2=1640/120 =13.67 A

c)

Since Input power =Output power

V2/V1=I1/I2

120/240 =I1/I3.67

I1=6.83 A

Resistance

R=V1/I1=240/6.83

R=35.12 ohms

Question 2:

a)

Induced emf

E=BLv =0.85*0.5*9

E=3.825 Volts

b)

Direction :Counter Clockwise

c)

To the Right

d)

Induced current

I=E/R =3.825/3 =1.275 A

Magnetic force

F=BIL =0.85*1.275*0.5

F=0.542 N

Question 3:

Magnetic field due to solenoid is

B=uo*n*I =(4pi*10^-7)*(40*10^2)*0.25

B=1.2566*10-3 T

Induced emf

E=NBA/t =2*(1.2566*10-3)*(6*10-4)/0.05

E=3.016*10-5 Volts or 30.16 uV

Question 4:

Area

A=pi*r2=pi*0.0682=0.01453 m2

a)

Flux=BACos(o)=0.212*0.01453*Cos(0) =3.08*10-3 Wb or 3.08 mWb

b)

Flux=BACos(o)=0.212*0.01453*Cos(52.6) =1.87*10-3 Wb or 1.87 mWb

c)

Flux=BACos(o)=0.212*0.01453*Cos(90) =0

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