Light of wavelength 525 nm is incident normally on a film of water 10 -4 cm thic

Question

Light of wavelength 525 nm is incident normally on a film of water 10-4 cm thick. The index of refraction of water is 1.33.

(a) What is the wavelength of the light in the water?
_______ nm
(b) How many wavelengths are contained in the distance 2t, where t is the thickness of the film? (Do not round your answer to a whole number.)

(c) What is the phase difference between the wave reflected from the top of the air-water interface and the one reflected from the bottom of the water-air interface after it has traveled this distance?
________rad

Explanation / Answer

a)  wavelength of the light in the water = lambda * (1/1.33)

= 525 * (1 / 1.33)

wavelength of the light in the water = 395 nm

b) distance 2 t = 2 mum

wavelengths contained in the distance 2t = 2 * 10-4 * 10-2/ 395

= 5.06 wavelengths

c) phase difference = ((5.06 - 4) * 360 ) -180

= 201.6 deg = 3.52 rad

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