2[ (.boy + lock wise DIRECTION solenoid has a radius of 1.27 cm, a length of 90

Question

2[ (.boy + lock wise DIRECTION solenoid has a radius of 1.27 cm, a length of 90 cm, 648 turns, 720 turns/m, and a current of 9.4 A t at its front and at its back as shown, Find the magnetic field at the center of the solenoid. (To show what's happening, the sketch is not to scale and shows many fewer turns at a much larger separation.) EQUATION USED SOLUTION ANSWER 9.4 A +9.4 MAGNITUDE DIRECTION 3. A long straight wire of radius 1.80 mm carries a 9.4 A current toward the bottom of the paper. Find the current magnetic field at point P 2.50 mm directly to the left of the center of the wire (0.70 mm from its surface). EQUATION USED SOLUTION ANSWER P . | | | MAGNITUDE DIRECTION a 0.9 mm as 1520 turns. TTs wound of wirethathas radu he turns (that is, in the "dough"), a distan d 4. A toroid (sometimes called a toroidal soleno Within toroid's center, you want a magnetic field of magnitude 6.5 mT. What must the current be ANSWER SOLUTION EQUATION USED

Explanation / Answer

2. given radius of solenoid, r = 1.27 cm = 0.0127 m

length = l = 0.9 m

number of turns, N = 648

current i = 9.4 A

Magnetic field at the center of the xolenoid = B

then B = mu*Ni/l = 4*pi*10^-7*648*9.4/0.9 = 0.0085049 T

3. radius of wire, r = 1.8 mm

current, i = 9.4 A

distance , d = 2.5 mm

now magnetic fiewld at a point at diatance d from the wire carrying a current i is given by

B = 2ki/d

so , B = 2*10^-7*9.4/2.5*10^-3 = 0.000752 T

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