2[C]) You bring an uncharged, identically shaped copper ball close to the first

Question

2[C]) You bring an uncharged, identically shaped copper ball close to the first one (without touching them to each other). Which combination of statements is most accurate?

(A) The equipotential surface between the copper balls is spherical
(B) The equipotential surface between the copper balls is not spherical
(C) There are no equipotential surfaces in the space around the balls
(D) The physical surfaces of the copper balls are equipotential surfaces
(E) The physical surfaces of the copper balls are not equipotential surfaces
(F) There is a voltage difference between the surfaces of the copper balls
(G) There is no voltage difference between the surfaces of the copper balls
(H) A voltage difference is induced across the surface of the new copper ball

3[C]) You observe a charged particle accelerate across a vacuum chamber from lower voltage to higher voltage. Which combination of statements are the most accurate conclusions you can draw?

(A) The particle is neutral
(B) The particle is positively charged
(C) The particle is negatively charged
(D) The particle is charged, but the sign is unknown
(E) The particle's potential energy increased
(F) The particle's potential energy decreased
(G) The particle's potential energy remained unchanged
(H) The particle was accelerated along the direction of the electric field
(I) The particle was accelerated opposite the direction of the electric field
(J) There is no electric field across the vacuum chamber
(K) There may not be an electric field across the vacuum chamber

Explanation / Answer

You did not mentioned here that other sphere is charged or not, but, I am taking the other sphere is charged.

Then,2).c. (D), (F) and (H) will be the more appropriate answer. (D). (F), and (H) all are properties of conductor.

3)c. And (C), (E), (I) will be the most appropriate answer. (C), (E), (I) all are the properties of negative charged particle.

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