2Mg+O 2 ---2MgO,rate=k[Mg][O 2 ] 2 What is the overall reaction order? What are

Question

2Mg+O2---2MgO,rate=k[Mg][O2]2 What is the overall reaction order? What are the units of the rate constant k for thisreaction?What would happen to the rate if [M] were doubled? What would happen to the rate if [O2] weredoubled? Would these 2 rates stay the same,double, triple, orquadruple? 2Mg+O2---2MgO,rate=k[Mg][O2]2 What is the overall reaction order? What are the units of the rate constant k for thisreaction?What would happen to the rate if [M] were doubled? What would happen to the rate if [O2] weredoubled? Would these 2 rates stay the same,double, triple, orquadruple? What is the overall reaction order? What are the units of the rate constant k for thisreaction?What would happen to the rate if [M] were doubled? What would happen to the rate if [O2] weredoubled? Would these 2 rates stay the same,double, triple, orquadruple?

Explanation / Answer

2Mg+O2---2MgO
rate=k[Mg][O2]2 overall reaction order = sum of the powers of theconcentration terms in the rate equation                                  =1 + 2                                 = 3 In general the units of nth order Rate constant is given bylit n-1 mole 1-n s -1 Since it is a 3rd order , the units of rate constantare  lit 3-1 mole 1-3 s-1                                                                                  lit 2mole -2 s -1 rate, r =k[Mg][O2]2 When the [Mg ] is doubled , then  new rate,r' =k[2Mg][O2]2                                                             r' =2k[Mg][O2]2                                                             r' = 2r So the rate is doubled When the [O2] is doubled , then  new rate,r' =k[Mg][2O2]2                                                             r' =22k[Mg][O2]2                                                             r' = 4r So the rate is four times i.e., quadruple. rate, r =k[Mg][O2]2 When the [Mg ] is doubled , then  new rate,r' =k[2Mg][O2]2                                                             r' =2k[Mg][O2]2                                                             r' = 2r So the rate is doubled When the [O2] is doubled , then  new rate,r' =k[Mg][2O2]2                                                             r' =22k[Mg][O2]2                                                             r' = 4r So the rate is four times i.e., quadruple. When the [O2] is doubled , then  new rate,r' =k[Mg][2O2]2                                                             r' =22k[Mg][O2]2                                                             r' = 4r So the rate is four times i.e., quadruple.

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