A black mare was crossed to a chestnut stallion, and produced a bay son and a ba

Question

A black mare was crossed to a chestnut stallion, and produced a bay son and a bay daughter. The two offspring were mated to each other, and over the course of several years they produced offspring of four colors: black, bay, chestnut, and liver. Crossing a liver grandson back to a black mare gave a black foal, and crossing a liver granddaughter to a chestnut stallion gave a chestnut foal. a. Develop a hypothesis for how coat color is determined and being inherited in this case. Be sure to state number of genes and number of alleles of each. b. For your hypothesis, assign gene symbols and indicate the genotype of parents and offspring in each cross.

Explanation / Answer

For the black parent - BB

The chestnut parent - bb

The bay daughter and son - Bb. The bay color displays both the colors of the parents. Hence, this shows codominance.

The cross of the F1 would be:

Bb x Bb

The progeny would be:

BB - black

Bb - bay

bb - chestnut

The color of liver is also recessive like the color of chestnut and has the same recessive genetics. Therefore it also has the same genotype of bb.

Crossing a liver grandson with bb genotype to a black mare would surely give a black foal as black is dominant. Crossing a liver granddaughter to a chestnut gives a chestnut since both are recessive colors in horses.

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