30.32 and the standard deviation is 10.89 The owner wants to know if the mean ag

ID: 3250445 • Letter: 3

Question

30.32 and the standard deviation is 10.89

The owner wants to know if the mean age of all customers is 25
years old. Use the given information to complete parts a through f.

a) What is the null hypothesis? answer is u=25 explain why?

b) Is the alternative one or two-sided? explain why?

c) What is the value of the test statistic? answer is 2.44 using formula

d) What is the P-value of the test statistic?

df = n- 1 = 25- 1 = 24

how do i can calculate P-value ? please explain step by step.

A store owner surveyed 25 randomly selected customers and found the ages shown (in years). The mean is

30.32 and the standard deviation is 10.89

The owner wants to know if the mean age of all customers is 25
years old. Use the given information to complete parts a through f.

a) What is the null hypothesis? answer is u=25 explain why?

b) Is the alternative one or two-sided? explain why?

c) What is the value of the test statistic? answer is 2.44 using formula

d) What is the P-value of the test statistic?

df = n- 1 = 25- 1 = 24

how do i can calculate P-value ? please explain step by step.

e) what do you conclude at 0.05? reject or fail to reject? explain how to make this decision.

One-Sample T

Test of null hypothesis = 25 vsalternative hypothesis : 25

N Mean StDev SE Mean 95% CI T P
25 30.32 10.89 2.18 (25.82, 34.82) 2.44 0.022

Its two tailed test.

P-value 0.022 < 0.05 we reject null hyothesis.

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