A.) what is the 99% confidence interval for 1972? Interpret this interval, which

Question

A.) what is the 99% confidence interval for 1972? Interpret this interval, which of the following are correct? a. We are 99% confidence that mean number of books read in 1972 is in the interval b. The probability that the interval does not contain the mean number of books read is 99% c. We are 99% confident that the mean number of books read in 1972 is not in the interval d. The probability that the interval contains the mean number of books read is 99%
B.) Were people reading more in 1972 than they are today?
a. No, people were reading less in 1972 than they are reading today b. Yes, people were reading more in 1972 than they are reading today c. People were reading approximately the same number of books in 1972 as they are today
1972 asked 1008 people. During the part year, alout how (a Contauct a 59ti the number books read either many books, either ha er paperback, did read al ack icen to view the table areas under tdatbution (use aseering order Round to twe dreinal places as needed Inevret cenidence interval which of the folowinn cometn OA No, people were reading less in 1972 than een are readng today O B Yes, people were readng in 1972 than they are reading laday more reading approximately the same number ofbeoks in 1972 as they are today OC. People

Explanation / Answer

here std error =std deviation/(n)1/2 =0.6463

for 99% CI,t=2.58

hence 99% confidence interval =sample mean -/+ t*std error =17.83 ; 21.17

a. We are 99% confidence that mean number of books read in 1972 is in the interval

B)

b. Yes, people were reading more in 1972 than they are reading today

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