A.) Two charges attract each other with a force of 5.0 N. What will be the force
ID: 2276146 • Letter: A
Question
A.) Two charges attract each other with a force of 5.0 N. What will be the force if the distance between them is reduced to one-ninth of its original value?
Explanation / Answer
A)
>F = ( q1 * q2 )/( 4 * pie* epsilon * R^2)
>so F is inversly propostional to distance square
>so if distance is reduced nine times force increases by 9^2 times
>so F = 5 * 9^2 = 405 N
> A) F = 405 N
B)
> acceleration = speed/time = 2.14 * 10^3 m/(s^2)
> F = m * a = ( 5.8 * 10^(-5) ) * 2.14 * 10^3 = 0.1242 N
>but F = E * q => E = F/q
>E = 0.01242 N/C
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