a physucal theraist wanted extimate the differencein the average pulse of men an

Question

 a physucal theraist wanted extimate the differencein the average pulse of men and womenafter stepping up and down on a 6 inch platform for 3 minutes. she randomly selected 51 men aand 70 women to participate in the study, the pulse of each subject wa recirded immediately after completing the stepping activity. use the information to construct a 90& confidence interval for the difference in population means . show work  please  

 women sample mean : 118.3 sample st. dev 14.2                mean sample mean: 112.3   sample st' dev: 11.3 

Explanation / Answer

n1 = 51 , n2 = 70 , mean1 = 112.3 , s1 = 11.3 , mean2 = 118.3 , s2 = 14.2

z value at 90% CI = 1.645

CI = ( mean1 - mean2) +/- z * sqrt(s1^2 / n1 + s2^2 /n2)

= ( 112.3 - 118.3) +/- 1.645 * sqrt(11.3^2/51+ 14.2^2/70)
= (-9.817, -2.183)

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