a particle with a speed of 5.0 x 10^10 m/s enters a magnetic field of .2 T perpe

Question

a particle with a speed of 5.0 x 10^10 m/s enters a magnetic field of .2 T perpendicularly. what is the radius of the circular motion if this particle is an electron, proton? a particle with a speed of 5.0 x 10^10 m/s enters a magnetic field of .2 T perpendicularly. what is the radius of the circular motion if this particle is an electron, proton? a particle with a speed of 5.0 x 10^10 m/s enters a magnetic field of .2 T perpendicularly. what is the radius of the circular motion if this particle is an electron, proton?

Explanation / Answer

here,

speed of electron , v = 5 * 10^10 m/s

magnetic feld , B = 0.2 T

mass of electron , me = 9.1 * 10^-31 kg

the radius of the circular motion be r

r = m * v / (e * B)

r = 9.1 * 10^-31 * 5 * 10^10 / (1.6*10^-19 * 0.2)

r = 1.42 m

the radius of the circular motion if this particle is an electron is 1.42 m

for proton

speed of proton , v = 5 * 10^10 m/s

magnetic feld , B = 0.2 T

mass of proton , mp = 1.67 * 10^-31 kg

the radius of the circular motion be r

r = mp * v / (e * B)

r = 1.67 * 10^-27 * 5 * 10^10 / (1.6*10^-19 * 0.2)

r = 2.61 * 10^3 m

the radius of the circular motion if this particle is an proton is 2.61 * 10^3 m

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