A university conducted a survey of 393 undergraduate students regarding satisfac
ID: 3233126 • Letter: A
Question
A university conducted a survey of 393 undergraduate students regarding satisfaction with student government. Results of the survey are shown in the table by class rank. Complete parts (a) through (d) below. (a) If a survey participant is selected at random, what is the probability that he or she is satisfied with student government? P(satisfied) = (Round to three decimal places as needed.) (b) If a survey participant is selected at random, what is the probability that he or she is a junior? P(junior) = (Round to three decimal places as needed.) (c) If a survey participant is selected at random, what is the probability that he or she is satisfied and a junior? P(satisfied and junior) = (Round to three decimal places as needed.)Explanation / Answer
(a)
Out of 393 participants 241 are satisfied with student goverment so requried probability
P(satisfied) = 241 / 393 = 0.6132
(b)
Out of 393 participants 98 are Juniors so requried probability
P(juniors) = 98 / 393 = 0.2494
(c)
Out of 393 participants 67 are Juniors and satisfied so requried probability
P(juniors and satisfied) = 67 / 393 = 0.1705
(d)
P(satisfied or junior) = P(satisfied)+P(junior) + P(satisfied and junior) = 0.6132 + 0.2494 - 0.1705 = 0.6921
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