A research team is hired to investigate the prevalence of periodontal disease in

Question

A research team is hired to investigate the prevalence of periodontal disease in a rural county with a below-average socioeconomic indicators. The team is given the task of surveying the area, and providing a brief examination of participants to correctly identify cases of periodontal disease and estimate an overall prevalence. If the team identifies an overall prevalence of above 25% (the national prevalence), they are to initiate an active campaign promoting healthy dental practice. Out of 2,879 participants surveyed, 754 were identified to have periodontal disease. Which formal test would be best for detecting if the prevalence of periodontal disease in the sample is greater than the minimum prevalence for intervention?

Chi-squared test

ANOVA

Inference about a proportion

Comparison of two proportions

T-test

Explanation / Answer

The answer is Inference about a proportion. This is because we know the population proportion to be 25% (0.25) and we know the sample proportion to be 754/2879 = 0.2619. So, a z- test for proportion can be used.

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