given any credit. Aservice station has both self-service and ful-service islands
ID: 3230077 • Letter: G
Question
Explanation / Answer
(a) P(X=0,Y=2) + P(X=1,Y=2) = 0.02+0.06 = 0.08
(b) P(X=0) = P(X=0, Y=0) + P(X=0, Y=1) + P(X=0, Y=2) = 0.16
P(X=1) = P(X=1, Y=0) + P(X=1, Y=1) + P(X=1, Y=2) = 0.34
P(X=2) = P(X=2, Y=0) + P(X=2, Y=1) + P(X=2, Y=2) = 0.50
Therefore the marginal distribution of X is
P(X less than or equal to x)= 0.16, x less than or equal to 0
= 0.50, x less than or equal to 1
= 1, x less than or equal to 2
P(Y=0) = P(X=0, Y=0) + P(X=1, Y=0) + P(X=2, Y=0) = 0.24
P(Y=1) = P(X=0, Y=1) + P(X=1, Y=1) + P(X=2, Y=1) = 0.38
P(Y=2) = P(X=0, Y=2) + P(X=1, Y=2) + P(X=2, Y=2) = 0.38
Therefore the marginal distribution of Y is
P(Y less than or equal to y)= 0.24, y less than or equal to 0
= 0.62, y less than or equal to 1
= 1, y less than or equal to 2
NO, X and Y are not independent.
P(X=0,Y=0)=0.1, P(X=0)*P(Y=0)=0.16*0.24
P(X=0,Y=0) not equal to P(X=0)*P(Y=0). Hence, X and Y are not independent.
(c) Conditional density of X given Y=2 = P(X, Y=2)/P(Y=2) = P(X, Y=2)/0.38
Conditional density of X=0 given Y=2 = P(X=0, Y=2)/0.38 =0.02/0.38 = 1/19
Conditional density of X=1 given Y=2 = P(X=1, Y=2)/0.38 =0.06/0.38 = 3/19
Conditional density of X=2 given Y=2 = P(X=2, Y=2)/0.38 =0.30/0.38 = 15/19
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