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give me the answers Solve 2 cos^2(x) + sin(x-) - 1 = 0 oil the interval [0, 2pi]

ID: 2906376 • Letter: G

Question

give me the answers

Solve 2 cos^2(x) + sin(x-) - 1 = 0 oil the interval [0, 2pi]. Work out the sum of all solutions, and list the denominator in lowest terms. Let u = (1,2) and v = (3,4). What is the projection of u onto v? An arbelos is created from three semi-circles; the diameter of each semi-circle lies along the same line and the semi-circles are tangent pairwise. Find the area of the shaded arbelos below. A deltoid is created by taking a circle of circumference C, placing a circle of circumference C/3 on the inside boundary of the circle, and then "rolling" that smaller circle along the boundary of the larger circle. The path traced out by the initial point of intersection between the circles creates a deltoid (see the shaded figure below). If the side length of the equilateral triangle is two, what is the area of the deltoid? Assume that the points on the deltoid bisect the sides of the triangle. The mean, mu, is an extremely important measurement in our everyday lives. The mean tells us what a person is likely to do on average. The mean is calculated by simply adding up all of the responses you have and then dividing by the number of responses. While this process sounds easy, it becomes a very tedious process for a large number of responses. To overcome this, we group the data by the possible responses and then use the dot product to calculate the mean. The table below shows a simulation for number of people per household in America. Compute the average number of people per household in America.

Explanation / Answer

26. 2cos^x +sin^x =1 [0,2pi]

cos^2x +1=1

cos^2x=0

cosx =0 ; x=pi/2 , 3pi/2 ; Sum= 4pi/2 =2pi

Demonimator 1 Option b)

27 u = <1,2> and v= <3,4>

||v||^2 = 25

Proj of v onto u ={ (u.v)/||v||^2}v

=( (3+8)/25)<3,4>

=11/25< 3, 4>

= <33/25, 44/25 >

Option a

29. pi(2)^2/2 -pi(1/2)^2(1/2) -pi(3/2)^2(1/2)

=pi/2 { 4 -1/4 -9/4 )

=pi/2{ 16-1-9}/4

=pi/2{6/4)

=3pi/4

Option a)