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Looking at a hypothetical set of data on the relationship between intrinsic moti

ID: 3221567 • Letter: L

Question

Looking at a hypothetical set of data on the relationship between intrinsic motivation and job performance. One could imagine that intrinsic motivation was measured through the use of a questionnaire and job performance was rated by a supervisor. Let’s imagine that the ratings for intrinsic motivation involved a 7-point Likert scale, with higher scores corresponding to higher intrinsic motivation. Job performance was rated on a 10 point scale, with higher ratings corresponding to better performance. In addition, let’s assume that the researchers hypothesize that there is a positive relationship between these factors, such that as intrinsic motivation increases job performance increases as well.

Making inferences: In sheet 5, you are given the values for r (Multiple R) and r2 (R Square). Notice that the value for Multiple R matches the value for the correlation we found in Sheet 4.

Below the regression statistics, you find an ANOVA table. In this table, the p value for significance is listed in cell F12. In cell A20, indicate whether the results suggest that there is or isn’t a relationship between intrinsic motivation and job performance.

Below the ANOVA table, you can find the coefficient for the intercept and for X Variable 1. The coefficient for the intercept corresponds to a in the regression equation, and the coefficient for X Variable 1 corresponds to b (the slope) in the regression equation. Write the regression equation (y = bx + a) for these data in cell A21, rounding to two decimal points. ( I need help with these formulas)

Correlation

Summary Output

L Column I Column 2 column i Column 2 0.16168939

Explanation / Answer

Sol;

multiple r=correlation coefficient=0.1616

there exists a weak positive relationship between  intrinsic motivation and job performance.

P VALUE=0.0222

P<0.05

REJECT NULL HYPOTHESIS

ACCEPT ALTERNATIVE HYPOTHESIS

MODEL IS SIGNIFICANT.

r sq=0.026=coeff of determiantion

=2.6% variation in Y is explained by model

regression equation is

Y=3.56+0.11 X1

SLOPE=0.11

Y INTERCEPT=3.56

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