A car dealer offers one of its models in 3 different styles (A, B, C) and two tr
ID: 3202161 • Letter: A
Question
A car dealer offers one of its models in 3 different styles (A, B, C) and two transmissions (manual and automatic). The table below indicates the number of cars sold in November 2016 for each combination of style and transmission. The event M indicates that a car had a manual transmission and event M' indicates an automatic transmission. Based on the information in the table, what is the probability that a randomly selected purchase in November 2016 was a car that... ...had a manual transmission? ...was style A? ...was either style A or B? ...was style C and had an automatic transmission? A candy makes its product in two colors (Red and Green) and two flavors manufacturer Apple and Berry). The percentages of each combination of color and flavor are given in the table below: Assume that you have a bag of the candy that is filled exactly using the percentages above and you randomly select a piece out of it. Based on the information in the table, what is the probability that the piece is... ...green? ...apple flavored? ...red and apple flavored? ...green or berry-flavored?Explanation / Answer
(a) Probability that the car had a manual transmission :
P = total number of manual transmission / total number of cars = 80/159 = 0.5031
(b) Probability that the car was style A:
P = total number of Style A/total number of cars = 60/159 = 0.3774.
(c) Probability Style A or B = P(Style A) + P(Style B) = 60/159 + 42/159 = 0.6415
(d) Probability that the car was Style C and had automatic transmission :
P = total number of Style C with automatic transmission / total number of cars = 35/159 = 0.2202.
7.
(a) P(green) = 0'41
(b) P(apple) = 0.30
(c) P(red and apple ) = P(red) X P(apple) = 0.59 X 0.30 = 0.177
(d) P(green or berry ) = P(green) + P(berry) - P(green and berry ) = 0.41 + 0.70 - 0.29 = 0.82
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