Transformations 3 A. Given the general equation for second-order kinetics, const

Question

Transformations 3 A. Given the general equation for second-order kinetics, construct a graph of the data tabulated below. Be sure to observe all the standard rules for constructing graphs. From your graph, caleulate the second order rate constant (k) and initial concentration (Co) with the appropriate units. CM 1.63 1.55 1.52 1.49 1.44 t sec 98 148 194 220 270 K= G= B. The specific rate constants (k) were determined for a decomposition reaction at four different temperatures. Recall that the relation, K = A e-Ea / RT can be transformed into the straight line expression. Ink = 1+In A Construct a graph of the data tabulated below. -1 K(sec) 9.85 103 2.47 102 5.96 102 1.11 10 TK 288 318 345 377 From the graph, calculate the activation energy (E) in joules/mol, given that the gas constant (R) is 8.314 Ea

Explanation / Answer

C0 = 1 / a = 1/ 0.5721671 =1.74774

k= 0.0004530

b)

-Ea/R = -3009.33133

Ea = 3009.33133 * 8.314 = 25019.5806776

Please rate

SUMMARY OUTPUT Regression Statistics Multiple R 0.993109369 R Square 0.986266218 Adjusted R Square 0.981688291 Standard Error 0.004078685 Observations 5 ANOVA df SS MS F Significance F Regression 1 0.00358398 0.00358398 215.4394706 0.000685919 Residual 3 4.9907E-05 1.66357E-05 Total 4 0.003633887 Coefficients Standard Error t Stat P-value Lower 95% Intercept 0.572167197 0.006023473 94.98958818 2.57199E-06 0.552997818 t 0.000453013 3.08637E-05 14.67785647 0.000685919 0.000354791

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