16.87 8.81 30.91 19.80 29.80 5.20 14.86 14.86 27.10 20.46 16.87 8.09 16.51 14.90

Question

16.87
8.81
30.91
19.80
29.80
5.20
14.86
14.86
27.10
20.46
16.87
8.09
16.51
14.90
15.35
15.42
15.72
33.67
9.72
18.30

The following data represent the concentration of dissolved organic carbon (mg/L) collected from 20 samples of organic soil Assume that the population is normally distributed Complete parts (a) through (c) on the right Find the sample mean. The sample mean is (Round to two decimal places as needed.) Find the sample standard deviation. The sample standard deviation is (Round to two decimal places as needed.) Construct a 80% confidence interval for the population mean mu The 80% confidence interval for the population mean is (Round to two decimal places as needed.)

Explanation / Answer

from above

std errir of mean =std deviation/(*n)1/2 =1.7086

for 80% CI, t=1.3277

hence confidence interval =sample mean -/+ t*std errior =15.3924 ; 19.9296

16.87 8.81 30.91 19.8 29.8 5.2 14.86 14.86 27.1 20.46 16.87 8.09 16.51 14.9 15.35 15.42 15.72 33.67 9.72 18.3 mean 17.6610 std deviation 7.6413

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