A school library is learning about student desires for library hours on Sunday m
ID: 3180605 • Letter: A
Question
A school library is learning about student desires for library hours on Sunday morning (9 a.m.–12 p.m.). The school took a random sample of 1,600 undergraduates (half men, half women) in each of four status levels (400 freshmen, 400 sophomores, 400 juniors, 400 seniors.) If the percentage of students preferring Sunday morning hours are represented below, what conclusions can the library reach?
Sen
Jun
Soph
Fresh
TOTAL
Women
72
60
35
20
187
Men
28
41
35
33
137
TOTAL
100
101
70
53
324
Complete the following steps:
Step 1: Hypotheses
Step 2: Determine Expected Results
Step 3: Calculate Chi-Square Value
Step 4: Find Chi Square Table Value based on Significance Level and Degrees of Freedom
Step 5: Compare Results and State Conclusion
Sen
Jun
Soph
Fresh
TOTAL
Women
72
60
35
20
187
Men
28
41
35
33
137
TOTAL
100
101
70
53
324
Explanation / Answer
step 1: null hypothesis:library hours timing for different category of students among gender is independent
alternate hypothesis:library hours timing for different category of students among gender is not independent
step 2)
step 3: chi square stat =18.853
step 4: degree of freedom =(row-1)*(column-1) =3
here chi square critical value for 3 df and 0.05 level = 7.8147
step 5) as chi stat is higher then chi critical we reject null hypothesis.
Observed O Sen Jun Soph Fresh Total Women 72 60 35 20 187 Men 28 41 35 33 137 Total 100 101 70 53 324 Expected E=rowtotal*column total/grand total Sen Jun Soph Fresh Total Women 57.716 58.293 40.401 30.590 187 Men 42.284 42.707 29.599 22.410 137 Total 100 101 70 53 324 chi square =(O-E)^2/E Sen Jun Soph Fresh Total Women 3.535 0.050 0.722 3.666 7.973 Men 4.825 0.068 0.986 5.004 10.883 Total 8.360 0.118 1.708 8.670 18.856Related Questions
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