A school library is learning about student desires for library hours on Sunday m
ID: 3181271 • Letter: A
Question
A school library is learning about student desires for library hours on Sunday morning (9 a.m.–12 p.m.). The school took a random sample of 1,600 undergraduates (half men, half women) in each of four status levels (400 freshmen, 400 sophomores, 400 juniors, 400 seniors.) If the percentage of students preferring Sunday morning hours are represented below, what conclusions can the library reach?
Complete the following steps:
Step 1: Hypotheses
Step 2: Determine Expected Results
Step 3: Calculate Chi-Square Value
Step 4: Find Chi Square Table Value based on Significance Level and Degrees of Freedom
Step 5: Compare Results and State Conclusion
Seniors Juniors Sophomores Freshman TOTAL Women 72 60 35 20 187 Men 28 41 35 33 137 TOTAL 100 101 70 53 324Explanation / Answer
1) null hypothesis: there is no association b/w gender and education level
alternate hypothesis:there is association b/w gender and education level
2,3)
chi square stat =18.856
4) chi critical =7.814
5) as chi stat is in critical region we reject null hypothesis and accpet that there is association b/w gender and association level
Observed O seniors Juniors Sophomores Freshmen Total Women 72 60 35 20 187 Men 28 41 35 33 137 Total 100 101 70 53 324 Expected E=rowtotal*column total/grand total seniors Juniors Sophomores Freshmen Total Women 57.716 58.293 40.401 30.590 187 Men 42.284 42.707 29.599 22.410 137 Total 100 101 70 53 324 chi square =(O-E)^2/E seniors Juniors Sophomores Freshmen Total Women 3.535 0.050 0.722 3.666 7.973 Men 4.825 0.068 0.986 5.004 10.883 Total 8.360 0.118 1.708 8.670 18.856Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.