The results of a recent study regarding heavy alcohol drinking and getting a liv
ID: 3176206 • Letter: T
Question
The results of a recent study regarding heavy alcohol drinking and getting a liver disease are shown in the following table Non-Drinkers Drinkers Totals Liver disease 68 82 150 No liver disease 32 18 50 Totals 100 100 200 We are interested in determining whether or not getting a liver disease is independent of heavy drinking. The expected frequency for the cell (No liver disease, Drinkers) is 75 82 25 18 The results of a recent study regarding heavy alcohol drinking and getting a liver disease are shown in the following table Non-Drinkers Drinkers Totals Liver disease 68 82 150 No liver disease 32 18 50 Totals 100 100 200 We are interested in determining whether or not getting a liver disease is independent of heavy drinking The value of the rest statistic is 3.062 1.307 10.516 5.227 The results of a recent study regarding heavy alcohol drinking and getting a liver disease are shown in the following table Non-Drinkers Drinkers Totals Liver disease 68 82 150 No liver disease 32 18 50 Totals 100 100 200 We are interested in determining whether or not getting a liver disease is independent of heavy drinking. The p-value of the test is between 0.025 and 0.01 more than 0.05 between 0.05 and 0.025 less than 0.01Explanation / Answer
Answer 14) From the two way contigency table given, we can see the frequency for the cell (No liver disease, Drinkers) is 18.
Answer 15) For determining whether or not getting a liver disease is independent of heavy drinking, we need to conduct chi square test of independence. I am using R software to conduct the test.
mydata <- data.frame(NonDrinkers=c(68,32),Drinkers=c(82,18))
rownames(mydata) <- c('Liver Disease','No liver disease')
mydata
chisq.test(mydata,correct = F)
Pearson's Chi-squared test
data: mydata
X-squared = 5.2267, df = 1, p-value = 0.02224
So, the value of test statistic is 5.227
Answer 16) As shown above, the p value os the test is 0.02224, so it is between 0.025 and 0.01.
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