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A plane wave traveling in air is incident on a perfectly conducting plane bounda

ID: 3163569 • Letter: A

Question

A plane wave traveling in air is incident on a perfectly conducting plane boundary at x=0. The incident electric field is given by: H = z(3 pi)^-1 exp [-j (8x + 6y)] Sketch the geometry of the problem. Show the directions of the electric field, magnetic field, and propagation constant. Is this a TE or TM wave? Explain. Find the propagation constant, angular frequency, and angle of incidence. Find the total field in air and sketch the variation of its amplitude as a function of the distance x. Calculate the distance from the plane boundary at which the amplitude of the field in air vanishes.

Explanation / Answer

k.r   = 8x + 6y

So k = 8i + 6j  

So plane propagation constant is 8i +6j

Direction of electricand magnetic field is perpendicular to the propagation vector and on the plane of propagation.

k^2 = w^2 *c

w = 10/ sqt(c)

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