1.) One point charge +Q is placed at the center of a square, and a second point

Question

1.) One point charge +Q is placed at the center of a square, and a second point charge -Q is placed at the upper-left corner of the square. It is observed that an electrostatic force of magnitude 2.0 N acts on the positive charge at the center. Now a third charge -Q is placed at the lower-left corner of the square. What is the magnitude of the net force that acts on the center charge now, assuming all charges have same magnitude?  N

2.) A +5.00E-6C point charge is placed at the 0.0 cm mark of a meter stick and a -4.00E-6 C point charge is placed at the 50.0 cm mark. At what point on a line through the ends of the meter stick is the electric field equal to zero?

A. 1.4 m from the 0 cm mark

B. 2.5 m from the 0 cm mark

C. 2.9 m from the 0 cm mark

D. 3.3 m from the 0 cm mark

E. 4.7 m from the 0 cm mark

Explanation / Answer

here,

1)

the initial force on the centre charge when only charge is placed on the left upper corner , F = 2 N

as the magnitude of charges is same

due to the symmetry formed

the net force in the vertical direction cancels out

the net force on the charge is towards left and has a magnitude , F' = 2 * F * cos(45)

F' = 2 * 2 * cos(45) = 2.83 N

the magnitude of net force acting on the centre charge is 2.83 N

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