A wire carries a 4A current along the axis through a magnetic field B = (5.0 + 7

Question

A wire carries a 4A current along the axis through a magnetic field B = (5.0 + 7.0)T If the wire experiences a force of 20 N A as a result, how long is the wire? 1.00m 0.71 m 1.5 m 0.75 m 1.1 m Two long parallel wires are placed side-by-side on a horizontal table. If the wires carry current in one wire is lifted slightly as the other is forced against the table's surface the wires attract each other both wires are forced against the table's surface the wires repel each other both wires are lifted slightly A point charge Q moves on the x axis in the positive direction with a speed of370 m/s. A point P is on the y axis at y = +80 mm The magnetic field produced at point Pas the charge moves through the origin, is equal to-o6 mu T A. When the charge is at x = +40 mm, what is the magnitude of the magnetic field at point P? 0.43 mu T 0.74 mu T 0.18 mu T 0.21 mu T 0.57 mu T As shown in the figure, a wire and a 10 resistor are used to form a circuit in the shape of a square, 20 cm by 20 cm. A uniform but non-steady magnetic field is directed into the plane of the circuit. The magnitude of the magnetic field is decreased from 1.5T to 0.5Tin time interval of 40 ms average induced current and its direction through the resistor, in this time interval, are closest to 100 mA, from b to a 200 mA, from a to b. 63 mA from a to b. 100 mA, from a to b. 63 mA, from b to a

Explanation / Answer

4) F = I ( L X B )

20 k = 4 [ i j k]

[ Lx 0 0]

[5 7 0]

5k = k(7Lx)

Lx = 5/7 = 0.714 m

so option b is the correct answer

5) forces acting on both the wire will be in opposite direction so option

a) one wire is lifted slightly and the other is forced against the table's surface

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