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1 48.5 32.4 11,168 2 48.2 31.7 11,150 3 44.5 31.9 11,186 4 44.7 36.6 11,381 5 49

ID: 3158898 • Letter: 1

Question

1

48.5

32.4

11,168

2

48.2

31.7

11,150

3

44.5

31.9

11,186

4

44.7

36.6

11,381

5

49.3

36.7

11,679

6

49.3

38.7

12,081

7

46.1

39.5

12,222

8

46.2

41.2

12,463

9

47.7

43.3

12,622

10

48.3

39.4

12,269

11

47.0

40.1

12,354

12

47.9

42.1

13,063

13

47.8

45.2

13,326

(Two Stocks and DJIA) The closing stock prices for each of two stocks were recorded over a 13-month period. The closing prices for the Dow Jones Industrial Average (DJIA) index were also recorded over the same time period. Month Stock 1 Stock 2 DJIA

1

48.5

32.4

11,168

2

48.2

31.7

11,150

3

44.5

31.9

11,186

4

44.7

36.6

11,381

5

49.3

36.7

11,679

6

49.3

38.7

12,081

7

46.1

39.5

12,222

8

46.2

41.2

12,463

9

47.7

43.3

12,622

10

48.3

39.4

12,269

11

47.0

40.1

12,354

12

47.9

42.1

13,063

13

47.8

45.2

13,326


Use the Excel data (Two Stocks and DJIA Model 1 Data) to develop a regression model (model 1) to predict the price of stock 1 based on DJIA. Let Y = price of stock 1 and X = DJIA.

Use the Excel data (Two Stocks and DJIA Model 2 Data) to develop a regression model (model 2) to predict the price of stock 2 based on DJIA. Let Y = price of stock 2 and X = DJIA.

(Two Stocks and DJIA) Use model 2 to predict the price of stock 2.
(a) The intercept (b0) is ___. [Answer format: two decimal places]  
(b) The slope coefficient (b1) is ___. [Answer format: four decimal places]  
(c) If the next month's DJIA is 13500, the predicted price of stock 2 is $___. (Hint: To avoid rounding errors, use the exact numbers in (a) and (b).) [Answer format: two decimal places]
Write your answer(s) as -12.34, 5.6789, 23.45

Explanation / Answer

Use the Excel data (Two Stocks and DJIA Model 1 Data) to develop a regression model (model 1) to predict the price of stock 1 based on DJIA. Let Y = price of stock 1 and X = DJIA.

The regression model to predict the price of stock 1 based on DJIA is given as below:

SUMMARY OUTPUT

Regression Statistics

Multiple R

0.187627675

R Square

0.035204145

Adjusted R Square

-0.05250457

Standard Error

1.603963525

Observations

13

ANOVA

df

SS

MS

F

Significance F

Regression

1

1.032618801

1.032619

0.401376

0.539329066

Residual

11

28.29968889

2.572699

Total

12

29.33230769

Coefficients

Standard Error

t Stat

P-value

Lower 95%

Upper 95%

Intercept

42.43247825

7.768625337

5.462032

0.000197

25.33384918

59.53110732

DJIA

0.000406958

0.000642354

0.633542

0.539329

-0.001006853

0.001820769

The regression equation is given as below:

Stock 1 = 42.4325 + 0.0004*DJIA

Use the Excel data (Two Stocks and DJIA Model 2 Data) to develop a regression model (model 2) to predict the price of stock 2 based on DJIA. Let Y = price of stock 2 and X = DJIA.

The regression model to predict the price of stock 2 based on DJIA is given as below:

SUMMARY OUTPUT

Regression Statistics

Multiple R

0.961226308

R Square

0.923956015

Adjusted R Square

0.917042925

Standard Error

1.250572788

Observations

13

ANOVA

df

SS

MS

F

Significance F

Regression

1

209.024437

209.024437

133.6531238

1.70492E-07

Residual

11

17.20325527

1.563932298

Total

12

226.2276923

Coefficients

Standard Error

t Stat

P-value

Lower 95%

Upper 95%

Intercept

-31.54007643

6.057015195

-5.20719784

0.000291216

-44.87147698

-18.20867588

DJIA

0.005789996

0.000500828

11.56084443

1.70492E-07

0.004687681

0.006892312

The regression equation is given as below:

Stock 2 = -31.54 + 0.0058*DJIA

(a) The intercept (b0) is ___. [Answer format: two decimal places]

The intercept is given as -31.54.

(b) The slope coefficient (b1) is ___. [Answer format: four decimal places]

The slope coefficient is given as 0.0058.

(c) If the next month's DJIA is 13500, the predicted price of stock 2 is $___.

The regression equation is given as

Stock 2 = -31.54 + 0.0058*DJIA

Stock 2 = -31.54 + 0.0058*13500

Stock 2 = $46.76

Predicted price of stock 2 is $46.76.

SUMMARY OUTPUT

Regression Statistics

Multiple R

0.187627675

R Square

0.035204145

Adjusted R Square

-0.05250457

Standard Error

1.603963525

Observations

13

ANOVA

df

SS

MS

F

Significance F

Regression

1

1.032618801

1.032619

0.401376

0.539329066

Residual

11

28.29968889

2.572699

Total

12

29.33230769

Coefficients

Standard Error

t Stat

P-value

Lower 95%

Upper 95%

Intercept

42.43247825

7.768625337

5.462032

0.000197

25.33384918

59.53110732

DJIA

0.000406958

0.000642354

0.633542

0.539329

-0.001006853

0.001820769