Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

1 2 3 4 5 6 7 8 9 An infinite line of charge with linear density 1 = -6.2C/m is

ID: 1528288 • Letter: 1

Question

1

2

3

4

5

6

7

8

9

An infinite line of charge with linear density 1 = -6.2C/m is positioned along the axis of a thick conducting shell of inner radius a = 2.9 cm and outer radius b = 4.8 cm and infinite length. The conducting shell is uniformly charged with a linear charge density 2 = 3.7 C/m.

1)

What is Ex(P), the electric field at point P, located at (x,y) = (-6.7 cm, 0 cm) ?

N/C

2)

What is Ey(P), the electric field at point P, located at (x,y) = (-6.7 cm, 0 cm) ?

N/C

3)

What is Ex(R), the electric field at point R, located a distance dR = 0.6 cm from the origin and making an angle of 30owith respect to the y-axis as shown?

N/C

4)

What is Ey(R), the electric field at point R, located a distance dR = 0.6 cm from the origin and making an angle of 30owith respect to the y-axis as shown?

N/C

5)

What is b, the linear charge density on the outer surface of the conducting shell ?

C/m

6)

What is a, the linear charge density on the inner surface of the conducting shell ?

C/m

7)

The charged conducting shell is now replaced by an uncharged conducting shell of the same dimensions. What is b, the linear charge density on the outer surface of the uncharged conducting shell ?

C/m

X 30

Explanation / Answer

1) Ex(P), the electric field at point P = 8.98 * 109 * (6.2 - 3.7) * 10-6 * 0.029/0.0672

                                                         = 1.45 * 105 N/C

2)   Ey(P), the electric field at point P = 8.98 * 109 * (6.2 - 3.7) * 10-6 * 0.048/0.0672

                                                         = 2.4 * 105 N/C

3) Ex(R), the electric field at point R =   8.98 * 109 * (6.2 - 3.7) * 10-6 * 0.029 * cos30/0.0062

                                                         = 1.566 * 107 N/C

4) Ey(R), the electric field at point R = 8.98 * 109 * (6.2 - 3.7) * 10-6 * 0.029 * sin30/0.0062

                                                         = 9.04 * 106 N/C