1 2 3 4 5 6 7 8 9 An infinite sheet of charge, oriented perpendicular to the x-a

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An infinite sheet of charge, oriented perpendicular to the x-axis, passes through x = 0. It has a surface charge density 1 = -3.6 C/m2. A thick, infinite conducting slab, also oriented perpendicular to the x-axis occupiees the region between a = 2.3 cm and b = 4.2 cm. The conducting slab has a net charge per unit area of 2 = 61 C/m2.

1)

What is Ex(P), the value of the x-component of the electric field at point P, located a distance 8.7 cm from the infinite sheet of charge?

N/C

2)

What is Ey(P), the value of the y-component of the electric field at point P, located a distance 8.7 cm from the infinite sheet of charge?

N/C

3)

What is Ex(R), the value of the x-component of the electric field at point R, located a distance 1.15 cm from the infinite sheet of charge?

N/C

4)

What is Ey(R), the value of the y-component of the electric field at point R, located a distance 1.15 cm from the infinite sheet of charge?

N/C

5)

What is b, the charge per unit area on thesurface of the slab located at x = 4.2 cm?

C/m2

6)

What is Ex, the value of the x-component of the electric field at a point on the x-axis located at x = 3.06 cm ?

N/C

7)

What is a, the charge per unit area on the surface of the slab located at x = 2.3 cm?

C/m2

Explanation / Answer

Make sure you convert to proper units
Epsilon = 8.85x10^-12

1) E = (1 + 2) / (2)(Epsilon)

2) y direction so it's 0 :)

3) E = (1 - 2) / (2)(Epsilon)

4) Y direction so it's 0 :)

I kinda forgot how to do these next few but one of the given formulas should work

5) b= (Efield)(Epsilon)
or
b = ((2 - 1) / 2 )

6) 0 its a conducting slab

7) E = (Efield at R)(Epsilon) (10^-6)

Use this step by. Steps formula..

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