lab has 26 students with an Exam 1 average of 81.5 %, and a sample standard devi

Question

lab has 26 students with an Exam 1 average of 81.5 %, and a sample standard deviation of 8.1 %. The instructor who manages all sections thinks the TA is fantastic and believes that the higher score for students may be due to the TA’s good instructional effort. scores appear to be more or less normally distributed. If the Exam 1 expected average score is 75.8 %, does that data support (at the 5% level of significance) the instructor’s view that has a significantly higher average? Ho µ 75.8% Ha µ > 75.8 % = 5 %

Explanation / Answer

here n = 26

degree of freedom = 25

alpha = 0.05

therefore for the right tail test the critical region from the t table = t>1.70

the t stat = (81.5 - 75.8)/ 8.1 = 0.70

as the t stat = 0.70<1.70

therefore we will not reject the null hypothesis

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