It was reported that in a survey of 4720 American youngsters aged 6 to 19, 18% w
ID: 3157781 • Letter: I
Question
It was reported that in a survey of 4720 American youngsters aged 6 to 19, 18% were seriously overweight (a body mass index of at least 30; this index is a measure of weight relative to height). Calculate a confidence interval using a 99% confidence level for the proportion of all American youngsters who are seriously overweight. (Round your answers to three decimal places.) Interpret the resulting interval. You may need to use the appropriate table in the Appendix of Tables to answer this question.Explanation / Answer
The 99% c.i=Ps+-Zsqrt[Ps(1-Ps)/N], where Ps is sample mean, Z is Z critical score at alpha=0.01, N is sample size.
=0.18+-2.58sqrt[0.18(1-0.18)/4720]
=0.1656 to 0.1944
Interpretation: Option II
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