ANOVA Table: Cumulative GPA Source of Variation Sum of Squares Degrees of Freedo
ID: 3157147 • Letter: A
Question
ANOVA Table: Cumulative GPA Source of Variation Sum of Squares Degrees of Freedom Mean Square F Treatment 32.17 2 16.09 4.44 Error 217.28 60 3.62 Total 249.45 62 ANOVA Table: Degrees Conferred Source of Variation Sum of Squares Degrees of Freedom Mean Square F Treatment 108.11 2 54.06 33.35 Error 97.26 60 1.62 Total 205.37 62 Pick one of the ANOVA Tables above and answer the questions below: 1. How many treatments are in the study? 2. What is the total sample size? 3. What is the critical value of F? (Use alpha = .01). 4. Write out the null and alternative hypotheses. 5. What is your decision regarding the null hypothesis? 6. Can we conclude the treatment means differ?
Explanation / Answer
Source SS df MS F
Teatment 108.11 2 54.06 33.35
Error 97.26 60 1.62
Total 205.37 62
1. Treatments(k): k-1=2, k=3
2. Total sample size, n: n-1=62, n=63
3. Critical value of F at df(2,60) and alpha=0.01 is 4.9774.
4. H0: mu1=mu2=mu3
H1: Not all the means are equal.
5. The test statistic falls in critical region, therefore, reject null hypothesis to cocnlude that atleast on emean is different from the another.
6. The treatment means differ.
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