The human resources department of a consulting firm gives a standard creativity
ID: 3155929 • Letter: T
Question
The human resources department of a consulting firm gives a standard creativity test to a randomly selected group of new hires every year. This year, 50 new hires took the test and scored a mean of 112.6 points with a standard deviation of 16.2. Last year, 100 new hires took the test and scored a mean of 117.4 points with a standard deviation of 18.2. Assume that the population standard deviations of the test scores of all new hires in the current year and the test scores of all new hires last year can be estimated by the sample standard deviations, as the samples used were quite large. Construct a confidence interval for , the difference between the mean test score of new hires from the current year and the mean test score of new hires from last year. Then complete the table below. Carry your intermediate computations to at least three decimal places. Round your answers to at least two decimal places.
Explanation / Answer
alpha / 2 = 0.025 Z = 1.96
I: 117.4 - 112.6 +/- 1.96 * srqt ( 16.2^2 / 50 + 18.2^2 / 100 )
4.8 +/- 5.73
-0.93 < miu 1 - miu2 < 10.53
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.