A telemarketing firm has studied the effects of two factors on the response to i
ID: 3152848 • Letter: A
Question
A telemarketing firm has studied the effects of two factors on the response to its television advertisements. The first factor is the time of day at which the ad is run, while the second is the position of the ad within the hour. The data in following table, which were obtained by using a completely randomized experimental design, give the number of calls placed to an 800 number following a sample broadcast of the advertisement. If we use Excel to analyze these data, we obtain the output in table below.
Perform graphical analysis to check for interaction between time of day and position of advertisement. Then test for interaction with = .05.
Make pairwise comparisons of the morning, afternoon, and evening times by using Tukey simultaneous 95 percent confidence intervals. (Round your answers to 2 decimal places. Negative amounts should be indicated by a minus sign.)
Make pairwise comparisons of the four ad positions by using Tukey simultaneous 95 percent confidence intervals. (Round your answers to 2 decimal places. Negative amounts should be indicated by a minus sign.)
Which time of day and advertisement position maximizes consumer response? Compute a 95 percent (individual) confidence interval for the mean number of calls placed for this time of day/ad position combination. (Round your answers to 2 decimal places.)
Position of Advertisement Time of Day On the Hour On the Half-Hour Early in Program Late in Program 10:00 morning 43 37 62 50 35 42 68 46 40 39 66 50 4:00 afternoon 62 57 86 68 60 64 81 60 60 53 80 67 9:00 evening 105 95 127 103 96 99 119 101 102 102 128 109Explanation / Answer
# i will answer 1st 4 subparts #
a) by looking at the graph one can comment that there is no interaction between variables
b) p-value>0.05 hence we fail to reject that there is no interaction.
c)Test the significance of position of advertisement effects with = .05.
F = 84.28, p-value = less than .001
pvalue<0.05 reject H0: position of the ads is important
d) margin of error=E=5.48
then CI for uM – uA:=(67-65.33-5.48,67-65.33+5.48)=(-3.81,7.81)
then CI for uM – uE:=(67-90.78-5.58,67-90.78+5.58)=(-29.26,-18.3)
then CI for uA – uE:=(65.33-90.75-5.48,65.33-90.75-5.48)=(-30.93,-19.97)
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